And I'm puzzled as to why we have to go through all these physics lessons to prove something.
I know, my head is hurting
But I am going to give this one more shot...no pun intended
If we are going off-topic with this, moderators, please accept my apologies and tell me to knock it off
It is the physical design of the rounds that do not allow for it, though. You can't say that physics allow it, because they don't allow it.
The physical design has little to do with it. Any object with the energy of a tank shell will do a lot of damage
Also, you're neglecting the actual resistance to sheering forces of the turret and its assembly.
What do you mean by shearing forces?
Anyway, if a round hits the turret in the right place (I've heard right where the turret meats the hull), the shell should be able to "wedge" itself between the turret and hull, and with the tremendous energy of the shell, it should be enough to pop off the turret.
For example, lets say only 5% of the energy of a shell is transfered vertically to the turret. That is 6,806,250 ft/lbs of energy that is still transfered. Now, if my calculations are correct, that equates to about 29 feet/second or about 20 mph. This is assuming the turret weighs 16,000 pounds. I don't know exactly how much a turret weighs. If anyone could give me a figure for a T72 turret, or something comperable, I would appreciate it.
So, even at a low energy transfer, physics still allow it. Weapon design, as I said above, has little to do with it. The big factor is where the shell impacts the tank.
-Student Pilot